SATHEE: Chemical and Ionic Equilibrium

Chemical and Ionic Equilibrium - Result Question 110

####54. One mole of nitrogen is mixed with three moles of hydrogen in a four litre container. If 0.25 per cent of nitrogen is converted to ammonia by the following reaction

$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), then$

calculate the equilibrium constant, $K_{c}$ in concentration units. What will be the value of $K_{c}$ for the following equilibrium?

$\frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g) ⇌ N H_{3} (g)$

$(1981, 4 M)$

Passage Based Questions

Thermal decomposition of gaseous $X_{2}$ to gaseous $X$ at $298 K$ takes place according to the following equation:

$X_{2} (g) ⇌ 2 X (g)$

The standard reaction Gibbs energy, $Δ_{r} G^{\circ}$ , of this reaction is positive. At the start of the reaction, there is one mole of $X_{2}$ and no $X$ . As the reaction proceeds, the number of moles of $X$ formed is given by $β$ . Thus, $β_{equilibrium}$ is the number of moles of $X$ formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.

(Given, $R = 0.083 L b a r K^{- 1} m o l^{- 1}$ )

Show Answer

Solution:

(i) $C H_{3} C O O H ⇌ C H_{3} C O O^{-} + H^{+}$

$C (1 - α) C α C α$

If no $H C l$ is present,

$\begin{aligned} [H C l] & = \frac{0.2}{2} = 0.10 M [C H_{3} C O O H] & = 0.10 M \end{aligned}$

The major contributor of $H^{+}$ in solution is $H C l$ .

$\begin{aligned} K_{a} & = \frac{C α (0.1)}{C (1 - α)} = 1.75 \times 10^{- 5} α & = 1.75 \times 10^{- 4} \end{aligned}$

(ii) $m m o l$ of $N a O H$ added $= \frac{6}{40} \times 1000 = 150$

$m m o l of H C l = 500 \times 0.2 = 100$

$m m o l$ of $C H_{3} C O O H = 500 \times 0.2 = 100$

After neutralisation, $m m o l$ of $C H_{3} C O O H = 50$

$m m o l$ of $C H_{3} C O O N a = 50$

$p H = p K_{a} = 4.75$

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Chemical and Ionic Equilibrium - Result Question 110

Passage Based Questions

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

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एनसीईआरटी व्यायाम वीडियो समाधान

Chemical and Ionic Equilibrium - Result Question 110

Passage Based Questions

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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