Chemical and Ionic Equilibrium - Result Question 106
####50. $N _2 O _4$ is $25 %$ dissociated at $37^{\circ} C$ and one atmosphere pressure. Calculate (i) $K _p$ and (ii) the percentage dissociation at $0.1 atm$ and $37^{\circ} C$.
$(1988,4 M)$
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Solution:
$$ \begin{aligned} & N _2 O _4 \rightleftharpoons 2 NO _2 \quad \text { Total } \ & p _i: \quad \begin{array}{cc} 1-\alpha & 2 \alpha \ \frac{1-\alpha}{1+\alpha} p & \frac{2 \alpha}{1+\alpha} p \end{array} \ & K _p=\frac{4 \alpha^{2}}{1-\alpha^{2}} p=\frac{4(0.25)^{2}}{1-(0.25)^{2}}=0.26 atm \end{aligned} $$
When $p=0.10 atm$
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