Carboxylic Acids and their Derivatives - Result Question 11
####11. When propionic acid is treated with aqueous sodium bicarbonate, $CO _2$ is liberated. The $C$ of $CO _2$ comes from
(a) methyl group
$(1999,2 M)$
(b) carboxylic acid group
(c) methylene group
(d) bicarbonate group
Show Answer
Answer:
Correct Answer: 11. (b)
Solution:
- $CH _3-CH _2-COOH+NaH \stackrel{}{C} O _3 \longrightarrow CH _3 CH _2 COONa$ $+H _2 O+\stackrel{}{C} O _2$
