Atomic Structure - Result Question 98

####74. The wavelength corresponding to maximum energy for hydrogen is 91.2nm. Find the corresponding wavelength for He+ion.

(2003, 2M)

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Answer:

Correct Answer: 74. (2.725×106M1)

Solution:

  1. The general Rydberg’s equation is

v¯=1λ=R(Z)2(1n121n22) 1λZ2 λ(He+)λ(H)=Z(H)2Z(He+)2=14 λ(He+)=λ(H)4=91.24nm=22.8nm



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