Atomic Structure - Result Question 51
####27. For a $d$-electron, the orbital angular momentum is $(1997,1 M)$
(a) $\sqrt{6}\left(\frac{h}{2 \pi}\right)$
(b) $\sqrt{2}\left(\frac{h}{2 \pi}\right)$
(c) $\left(\frac{h}{2 \pi}\right)$
(d) $2\left(\frac{h}{2 \pi}\right)$
Atomic Structure
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Solution:
- The orbital angular momentum $(L)=\sqrt{l(l+1)} \frac{h}{2 \pi}$
$$ =\sqrt{6} \frac{h}{2 \pi}(l=2 \text { for } d \text {-orbital }) $$
