Atomic Structure - Result Question 38
####14. The energy of an electron in the first Bohr orbit of $H$-atom is $-13.6 eV$. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)
(1988)
(a) $-3.4 eV$
(b) $-4.2 eV$
(c) $-6.8 eV$
(d) $+6.8 eV$
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Answer:
Correct Answer: 14. (a)
Solution:
- Energy of electron in H-atom is determined by the expression:
$$ E _n=-\frac{13.6}{n^{2}} eV \quad \text { where, } \quad n=1,2,3, \ldots $$
In excited states, $E _2=-\frac{13.6}{4}=-3.4 eV$
$$ E _3=-\frac{13.6}{9}=-1.51 eV \text { etc. } $$
