Atomic Structure - Result Question 105

####81. What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n=4 to n=2 of He+spectrum?

(1993, 3M)

Show Answer

Solution:

  1. The expression for transition wavelength is given by Rydberg’s equation :

1λ=RHZ2(1n121n22)

Equating the transition wavelengths of H atom and He+ion,

RH(1n121n22)=RH(422442)

Equating termwise on left to right of the above equation gives n1=1 and n2=2



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक