Atomic Structure - Result Question 100

####76. An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.54\AA.

(1997 (C), 2M)

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Answer:

Correct Answer: 76. (471nm)

Solution:

  1. If accelerated by potential difference of V volt, then

12mv2=eV p22m=eV, here p=momentum(mv)

Using de-Broglie equation, λ=hp=h2meV

1.54×1010=6.625×1034(2×9.1×1031×1.6×1019V)1/2

Solving for V gives : V=63.56V.



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