Aromatic Compounds Containing Nitrogen - Result Question 10
####10. What will be the major product in the following mononitration reaction?
(2019 Main, 10 Jan II)
(a)
(c)
(b)
(d)
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Answer:
Correct Answer: 10. $\left({ }^{*}\right)$
Solution:
- Here, in mononitration the electrophile produced from mixed acid $\left(HNO _3+\right.$ conc. $\left.H _2 SO _4\right)$ is $\stackrel{+}{N} O _2$.
Ring- $(A)$ is activated, i.e. becomes more nucleophilic by the $+R$ effect of the $-\ddot{N} H-$ group and it becomes $o / p$-directing towards the electrophile, $NO _2^{+}$in the $ArS _E 2$ reaction. For mononitration, $\stackrel{\oplus}{N} O _2$ will preferably come at p-position,
whereas the ring- $(B)$ gets deactivated by $-R$ - effect of the $\stackrel{O}{|}-C-$ group,
