Alkyl Halides - Result Question 8
####8. The major product of the following reaction is
(2019 Main, 12 Jan II)
(a) $CH _3 CH _2 \underset{NH _2}{CH}-\underset{NH _2}{CH _2}$
(b) $CH _3 CH=CHCH _2 NH _2$
(c) $CH _3 CH=C=CH _2$
(d) $CH _3 CH _2 C \equiv CH$
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Solution:
Key Idea Both alc. $KOH$ and $NaNH _2$ in liquid $NH _3$ are dehydrohalogenating reagents. On comparative terms $NaNH _2 /$ liquid $NH _3$ is stronger in action.
The reaction proceeds as :
Thus, option (d) is the correct answer.
