Alkyl Halides - Result Question 17
####17. The major product obtained in the following reaction is
$$ C _6 H _5 \xrightarrow{Br} C _6 H _5 \xrightarrow[\Delta]{{ }^{t} BuOK} $$
(2017 Main)
(a) $( \pm) C _6 H _5 CH\left(O^{t} Bu\right) CH _2 C _6 H _5$
(b) $C _6 H _5 CH=CHC _6 H _5$
(c) $(+) C _6 H _5 CH\left(O^{t} Bu\right) CH _2 C _6 H _5$
(d) $(-) C _6 H _5 CH\left(O^{t} Bu\right) CH _2 C _6 H _5$
Show Answer
Solution:
- An alkyl halide in presence of a bulkier base removes a proton from a carbon adjacent to the carbon bonded to the halogen. This reaction is called $E 2$ ( $\beta$-elimination reaction).
