Alkyl Halides - Result Question 16

####16. 3-methyl-pent-2-ene on reaction with $HBr$ in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is

(a) six

(b) zero

(c) two

(d) four

(2017 Main)

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Solution:

  1. The number of stereoisomers in molecules which are not divisible into two equal halves and have $n$ number of asymmetric C-atoms $=2^{n}$.

3-methyl-pent-2-ene on reaction with $HBr$ in presence of peroxide forms an addition product i.e. 2-bromo-3-methyl pentane. It has two chiral centres. Therefore, 4 stereoisomers are possible



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