Alkyl Halides - Result Question 16
####16. 3-methyl-pent-2-ene on reaction with $HBr$ in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is
(a) six
(b) zero
(c) two
(d) four
(2017 Main)
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Solution:
- The number of stereoisomers in molecules which are not divisible into two equal halves and have $n$ number of asymmetric C-atoms $=2^{n}$.
3-methyl-pent-2-ene on reaction with $HBr$ in presence of peroxide forms an addition product i.e. 2-bromo-3-methyl pentane. It has two chiral centres. Therefore, 4 stereoisomers are possible