Aliphatic Compounds Containing Nitrogen - Result Question 15
####16. In the Hofmann-bromamide degradation reaction, the number of moles of $NaOH$ and $Br _2$ used per mole of amine produced are
(2016 Main)
(a) four moles of $NaOH$ and two moles of $Br _2$
(b) two moles of $NaOH$ and two moles of $Br _2$
(c) four moles of $NaOH$ and one mole of $Br _2$
(d) one mole of $NaOH$ and one mole of $Br _2$
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Answer:
Correct Answer: 16. (c)
Solution:
- Hofmann-bromamide degradation reaction is given as:
$R CONH _2+4 NaOH+Br _2 \longrightarrow \underset{\left(1^{\circ} \text { amine }\right)}{R NH _2}$
$$ +Na _2 CO _3+2 NaBr+2 H _2 O $$
Hence, four moles of $NaOH$ and one mole of $Br _2$ are used.
