Aldehydes and Ketones - Result Question 57
####67. Write the intermediate steps for each of the following reactions
(i) $C _6 H _5 CH(OH) C \equiv CH \xrightarrow{H _3 O^{+}} C _6 H _5 CH=CHCHO$
(ii)
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Solution:
- (i) $C _6 H _5-\underset{O}{O H} \underset{C}{CH}-C \equiv C-H$
$\xrightarrow{-H^{+}} C _6 H _5-CH=CH-\stackrel{O}{C}-H$
$\underset{\text { tautomerisation }}{\rightleftharpoons} C _6 H _5-CH=C=\underset{H}{C}-OH$
(ii)
$\xrightarrow{-H^{+}}$
