SATHEE: magnetism-and-matter Question 22

चुंबकत्व और पदार्थ

Question: Q. 8. The vertical component of Earth’s magnetic field at a place is $\sqrt{3}$ times the horizontal component. What is the value of angle of dip at this place?

R [OD 2012]

Sol. We know that

Vertical component of Earth’s magnetic field,

$B_{v} = B \sin θ$

Horizontal component of Earth’s magnetic filed,

$\begin{aligned} H = B \cos θ & Where θ is the angle of dip \end{aligned}$

$1 / 2$

According to the question, at a place

$\frac{B_{v}}{H} = \sqrt{3}$

$1 / 2$

$\Rightarrow$ B $\frac{B \sin θ}{B \cos θ} = \sqrt{3}$

$\begin{aligned} \tan θ & = \sqrt{3} θ & = 60^{\circ} \end{aligned}$

Q.9. Give two points to distinguish between a paramagnetic and a diamagnetic substance.

R [Foreign 2014]

(Any two) $1 + 1$

Q. 10. The susceptibility of a magnetic material is $- 2.6 \times 10^{5}$ . Identify the type of magnetic material and state its two properties.

R [Delhi I, II, III 2012]

Show Answer

Solution:

Ans. Diamagnetic material.

Properties :

(i) They have the tendency to move from stronger to weaker part of the external magnetic field.

(ii) They expel magnetic field lines.

(iii) Such substances are repelled by a bar magnet. (iv) When placed in an external magnetic field, a net magnetic dipole moment is developed inside it which is in a direction opposite to that of the applied magnetic field.

(Any two) $1 / 2 + 1 / 2$

[CBSE Marking Scheme 2012]

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चुंबकत्व और पदार्थ

विषयसूची

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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