Question: Q. 5. Two magnets of magnetic moment M and M3 are joined to form a cross. The combination is suspended in a uniform magnetic field B. The magnetic moment now makes an angle θ with the field direction. Find the value of angle θ.

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Solution:

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[CBSE SQP, 2011]

In equilibrium condition, torque on both magnets are equal and opposite. Hence,

(1)MBsinθ=3Msin(90θ) MBsinθ=3Mcosθ sinθcosθ=3MM tanθ=3 or θ=60



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