Question: Q. 2. A capacitor of unknown capacitance is connected across a battery of V volt. A charge of 360μC is stored in it. When the potential across the capacitor is reduced by 120 V, the charge stored in the capacitor becomes 120μC. Calculate V and the unknown capacitance. What would have been the charge on the capacitor if the voltage were increased by 120 V? U [Delhi (Comptt.) I 2017]

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Solution:

Ans. Calculation of V and unknown capacitance 2 Calculation of charge when voltage is increased by 120 V Capacitance

Also,

C=Q1V1 C=Q2V2 and C=Q3V3 360μCV=120μC(V120)

So,

3V360V=V

V=180 V

C=360μV180V=2μF

2μF=Q3300

Q3=600μC

Detailed Answer :

(i) Let the initial yoltage =V volts

Charge stored, Q1=360μC

(i)Q1=CV1=CV

Now the changed potential

(ii)V2=(V120) volts  Q2=120μC Q2=CV2

Now divide equation (i) by (ii), we have:

Q1Q2=CV1CV2 360μC120μC=VV120

On solving, we get V=180 volts

Now value of unknown capacitance C can be calculated as

C=Q1V=360×106180 F =2×106 F=2μF

(ii) When the voltage applied increases to 120 V, then

V3=180+120=300 V1/2

Finally the charge stored in the capacitor will be :

Q3=CV3 =2×106×300C =600μC



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