Question: Q. 8. A point charge
(i) The magnitude and sign of the charge induced on the inner and outer surface of the conducting shell.
(ii) The magnitude of electric field vector at a distance (i)
A&E [CBSE SQP 2017-18]
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Solution:
Ans. (i) As the electrostatic field inside a conductor is zero, using Gauss’s law, charge on the inner surface of the shell
Charge on the outer surface of the shell
(ii) To show using Gauss’s law
Expression for electric field for radius,
Expression for electric field for radius,
[CBSE Marking Scheme, 2017]
Detailed Answer :
(i) Charge placed at the centre of a shell is
A charge of
(ii) The electric flux is electric field times the area of spherical surface
So electric field outside the sphere
Magnitude of electric field vector at a distance
Magnitude of electric field vector at a distance