Question: Q. 3. Given a uniform electric field E=5×103i^ N/C. Find the flux of this field through a square of side 10 cm on a side whose plane is parallel to the yz plane. What would be the flux through the same square if the plane makes a 30 angle with the x-axis?

A [Delhi I, II, III, 2014]

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Solution:

Ans. Flux of this field through a square of 10 cm1 Flux of the square with normal making 30 angle

ϕ=EAcosθ1/2 ϕ=5×103×102cos0NC1 m2 ϕ=50NC1 m21/2 ϕ=5×103×102cos60NC1 m21/2 =25NC1 m21/2

[CBSE Marking Scheme, 2014]

Detailed Answer :

Given :

E=5×103ı^ N/C along (+) positive direction of x-axis.

Surface area, A=10 cm×10 cm

=0.10 m×0.10 m =102 m2

(i) In case of plane parallel to yz plane, normal to plane will be along x-axis, so ϕ=0

Electric flux will be calculated using ϕ=|E|Acosθ

1/2

=5×103×102×cos0

=50Nm2/C

(ii) Since plane is making an angle of 30 with x-axis, so normal to its plane will make 60 with x-axis, so θ=60 Now finding Electric flux again with ϕ=|E|Acosθ =5×103×102×cos60 1/2 =25Nm2/C

1/2

Short Answer Type Questions-II



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