Question: Q. 3. State Gauss’s law in electrostatics.
R [Delhi I, II, III 2016]
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Solution:
Ans. Gauss’s law in electrostatics : “The surface integral of electrostatic field
$$ \begin{equation*} \phi_{\mathrm{E}}=\oint \overrightarrow{\mathrm{E}} \cdot d \overrightarrow{\mathrm{S}}=\frac{\mathrm{Q}{\text {enclosed }}}{\varepsilon{0}} \tag{1} \end{equation*} $$
[CBSE Marking Scheme, 2016]
Commonly Made Error
- Most of the candidates are unable in stating gauss law correctly. Key words like net charges, closed surface etc. are missed by students. Some candidates write magnetic flux instead of electric flux.
