Question: Q. 3. Derive an expression for electric field of a dipole at a point on the equatorial plane of the dipole. How does the field vary at large distances?

A [SQP 2017-18]

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Solution:

Ans. (i) Derivation

(ii) At large distances, $\vec{E} \propto \frac{1}{r^{3}}$

[CBSE Marking Scheme, 2017]

Detailed Answer :

(i) Try yourself, similar to Q. 1 (i) Short Answer Type Questions-II

(ii) Electric field, $\quad E=\frac{-p}{4 \pi \varepsilon_{0}\left(r^{2}+a^{2}\right)^{3 / 2}}$

If the dipole is at large distance $r»a$

$$ \begin{align*} \boldsymbol{E} & =\frac{-p}{4 \pi \varepsilon_{0} r^{3}} \ |\vec{E}| & \propto \frac{1}{r^{3}} \end{align*} $$



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