Question: Q. 6. A proton and a deuteron are accelerated through the same accelerating potential. Which one of the two has :

(i) greater value of de-Broglie wavelength associated with it, and

(ii) less momentum ?

Give reasons to justify your answer.

U] [Delhi I, II, III 2014]

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Solution:

Ans. (i) de-Broglie wavelength is given by

λ=h2mqV

As mass of proton < mass of deuteron and qp=qd and V is same.

λp>λd for same accelerating potential.

(ii) Momentum =hλ

λp>λd

Momentum of proton will be less than that of deuteron.

[CBSEMarking Scheme 2014]



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