Question: Q. 3. A Proton and an $\alpha$-particle are accelerated through the same potential difference. Which one of the two has (i) greater de-Broglie wavelength, and (ii) less kinetic energy? Justify your answer.
U [OD North 2016]
Show Answer
Solution:
Ans. (i) Try yourself Similar to Q. 1 SATQ-I
(ii)
K.E. $=q V$
$\therefore q$ is less for proton, we have
(K.E. $){\text {proton }}<(\text { K.E. }){\alpha \text {-particle }}$
(Also accept if the student writes $\frac{(\text { K.E. }){\alpha}}{(\text { K.E. }){p}}=2$ )
[CBSE Marking Scheme 2016]
