Question: Q. 5. A proton and an electron have same kinetic energy. Which one has greater de-Broglie wavelength and why?
[O.D. I, II, III 2012]
Solution:
Ans. Electron
$$ \lambda \propto \frac{1}{\sqrt{m}} \text { (for same kinetic energy) } 1 / 2 $$
[CBSE Marking Scheme 2012]
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