Question: Q. 3. Explain giving reasons for the following :

(i) Photoelectric current in a photocell increases with the increase in the intensity of the incident radiation.

(ii) The stopping potential (V0) varies linearly with the frequency (v) of the incident radiation for a given photosensitive surface with the slope remaining the same for different surfaces.

(iii) Maximum kinetic energy of the photoelectrons is independent of the intensity of incident radiation.

U [OD II 2017]

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Solution:

Ans. (i) The collision of a photon can cause emission of a photoelectron (if the frequency is above the threshold frequency). As intensity if the frequency increases, number of photons increases. Hence, the current increases.

(ii) We have,

Graph of 2s,v is a straight line and slope (=he)

is a constant.

1/2

(iii) Maximum K.E. for different surfaces =h(vv0)1/2 Hence, it depends on the frequency and not on the intensity of the incident radiation.

[CBSE Marking Scheme 2017]



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