Question: Q. 10.
$$ \begin{array}{rlrl} \text {
Solution:
Ans. } & E_{V} & =\phi_{0}+K_{\max } \ \text { As } & & \phi_{0} & =0 \ \Rightarrow & E_{\mathbf{V}} & =K_{\max } \ \Rightarrow & K_{\max } & =\frac{p^{2}}{2 m}=E_{\mathbf{V}} \ \Rightarrow & & p & =\sqrt{2 m E_{\mathrm{V}}} \end{array} $$
[CBSE Marking Scheme, 2014]
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