Question: Q. 2. What is relaxation time ? Derive an expression for resistivity of a wire in terms of number density of free electrons and relaxation time.

A[SQP I 2017-18]

Show Answer

Solution:

Ans. Definition and Derivation.

[CBSE Marking Scheme, 2017]

Detailed answer :

(i) Relaxation time shows the effect of collisions among the electrons and ions or impurities on electrical conduction in a metal. It is the time taken for the drift velocity to decay $1 / e$ of its initial value.

As drift velocity increases, relaxation time decreases since the electrons move the distance in which they frequently collide faster.

(ii) When a potential difference $V$ is applied across conductor of length $l$, then drift speed of electron will result as :

$$ \begin{aligned} v_{d} & =\frac{e E \tau}{m} \ & =\frac{e V \tau}{l m} \end{aligned} $$

$$ \because\left[E=\frac{V}{l}\right] $$

The electric current through the conductor and drift speed are linked as $I=n e A v_{d}$ where,

$n=$ number density of electrons

$e=$ electronic charge

$A=$ area of cross section

$v_{d}=$ electron drift speed

$\therefore \quad I=n e A\left(\frac{e V \tau}{l m}\right)$

So, $\quad \frac{V}{I}=\frac{m l}{n e^{2} \tau A}$

At constant temperature :

$\frac{V}{I}=R$

Hence,

Comparing above expression with

$$ R=\rho \frac{l}{A} $$

where, $\rho=$ specific resistance

$$ \rho=\frac{m}{n e^{2} \tau} $$



विषयसूची

जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक