Question: Q. 17. In the circuit shown in the figure, find the total resistance of the circuit and the current in the arm CD
A [Foreign Set II 2014]
Show Answer
Solution:
Ans. In a steady state (when capacitor is fully charged no current flows through branch CEF and the given circuit reduced to
$$ \Rightarrow \quad R_{e q(A D)}=2 \Omega $$
Total resistance, $R_{A F}=2+3=5 \Omega$
Hence
$$ I=\frac{15}{5} \mathrm{~A}=3 \mathrm{~A} $$
Current through, $C D, I_{1}=\frac{3}{9} \times I=1 \mathrm{~A}$
