Question: Q. 6. Calculate the shortest wavelength of the spectral lines emitted in Balmer series. (Given Rydberg constant, $R=10^{7} \mathrm{~m}^{-1}$ )

R] [Delhi OD 2016]

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Solution:

Ans.

$$ \frac{1}{\lambda}=R\left(\frac{1}{2^{2}}-\frac{1}{\infty^{2}}\right) $$

For shortest wavelength, $n=\infty$

Therefore, $\frac{1}{\lambda}=\frac{R}{4}$

$$ \Rightarrow \quad \lambda=\frac{4}{R}=4 \times 10^{-7} \mathrm{~m} $$

[CBSE Marking Scheme 2016]



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