Work Energy And Power Question 75

Question: Two particles of masses m1 and m2 in projectile motion have velocities v1 and v2 respectively at time t = 0. They collide at time t0 . Their velocities become v1 and v2 at time 2t0 while still moving in air. The value of |(m1v1+m2v2)(m1v1+m2v2) | is [IIT-JEE Screening 2001]

Options:

A) Zero

B) (m1+m2)gt0

C) 2(m1+m2)gt0

D) 12(m1+m2)gt0

Show Answer

Answer:

Correct Answer: C

Solution:

The momentum of the two-particle system, at t = 0 is Pi=m1v1+m2v2 Collision between the two does not affect the total momentum of the system.

A constant external force (m1+m2)g acts on the system. The impulse given by this force, in time t = 0 to t=2t0 is (m1+m2)g×2t0 \ |Change in momentum in this interval =|m1v1+m2v2(m1v1+m2v2)|=2(m1+m2)gt0



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