Work Energy And Power Question 49
Question: A body of mass 2 kg is projected vertically upwards with a velocity of $ 2m{{\sec }^{-1}} $ . The K.E. of the body just before striking the ground is [EAMCET 1980]
Options:
A) 2 J
B) 1 J
C) 4 J
D) 8 J
Show Answer
Answer:
Correct Answer: C
Solution:
If particle is projected vertically upward with velocity of 2m/s then it returns with the same velocity. So its kinetic energy $ =\frac{1}{2}mv^{2}=\frac{1}{2}\times 2\times {{(2)}^{2}}=4J $
