SATHEE: Work Energy And Power Question 43

Work Energy And Power Question 43

Question: If the K.E. of a body is increased by 300%, its momentum will increase by [JIPMER 1978; AFMC 1993; RPET 1999; CBSE PMT 2002]

Options:

A) 100%

B) 150%

C) $\sqrt{300}$

D) 175%

Show Answer

Answer:

Correct Answer: A

Solution:

Let initial kinetic energy, $E_{1} = E$

Final kinetic energy, $E_{2} = E + 300$ of E = 4E As $P \propto \sqrt{E}$

therefore $\frac{P_{2}}{P_{1}} = \sqrt{\frac{E_{2}}{E_{1}}} = \sqrt{\frac{4 E}{E}} = 2$

therefore $P_{2} = 2 P_{1}$

therefore $P_{2} = P_{1} + 100$ of $P_{1}$

i.e. Momentum will increase by 100%.

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Work Energy And Power Question 43

Question: If the K.E. of a body is increased by 300%, its momentum will increase by [JIPMER 1978; AFMC 1993; RPET 1999; CBSE PMT 2002]

Options:

Answer:

Solution:

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