Work Energy And Power Question 279

Question: Two small bodies of masses ’m’ and ‘2m’ are placed in a fixed smooth horizontal circular hollow tube of mean radius ‘r’ as shown. The mass ’m’ is moving with speed ‘u’ and the mass ‘2m’ is stationary. After their first collision, the time elapsed for next collision is [ coefficient of restitution e = 1/2 ]

Options:

A) 2πru

B) 4πru

C) 3πru

D) 12πru

Show Answer

Answer:

Correct Answer: B

Solution:

[b] If just after collision, relative velocity = v then

vu=12ωrel=vr=u2r

time between 1st and 2nd collision, t=2πωrel

=4πru



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