Work Energy And Power Question 278

Question: Three masses m, 2m and 3m are moving in x-y plane with speed 3u, 2u and u respectively as shown in figure. The three masses collide at the same point at P and stick together. The velocity of resulting mass will be

Options:

A) u12(i^+3j^)

B) u12(i^3j^)

C) u12(i^+3j^)

D) u12(i^3j^)

Show Answer

Answer:

Correct Answer: D

Solution:

[d] From the law of conservation of momentum we know that,

m1u1+m2u2+=m1v1+m2v2+ Given m1=m,m2=2mandm3=3m

and u1=3u,u2=2uandu3=u

Let the velocity when they stick =v

Then, according to question, m×3u(i^)+2m×2u(i^cos60j^sin60)

+3m×u(i^cos60+j^sin60)=(m+2m+3m)v

3mui^4mui^24mu(32j^)3mui^2

+3mu(32j^)=6mv

mui^32mui^32muj^=6mv

12mui^32muj^=6mv

v=u12(i^3j^)



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