SATHEE: Work Energy And Power Question 265

Work Energy And Power Question 265

Question: A 10 H.P. motor pumps out water from a well of depth 20 m and fills a water tank of volume 2380 litres at a height of 10 m from the ground. The running time of the motor to fill the empty water tank is $(g = 10 m s^{- 2})$

Options:

A) 5 minutes

B) 10 minutes

C) 15 minutes

D) 20 minutes

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Volume of water to raise =223807 $= 22380 \times 10^{- 3} m^{3}$

$P = \frac{m g h}{t} = \frac{V ρ g h}{t} \Rightarrow t = \frac{V ρ g h}{p}$

$t = \frac{22380 \times 1 0^{- 3} \times l 0^{3} \times l 0 \times l 0}{10 \times 746}$

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Work Energy And Power Question 265

Question: A 10 H.P. motor pumps out water from a well of depth 20 m and fills a water tank of volume 2380 litres at a height of 10 m from the ground. The running time of the motor to fill the empty water tank is (g=10ms−2)

Options:

Answer:

Solution:

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Question: A 10 H.P. motor pumps out water from a well of depth 20 m and fills a water tank of volume 2380 litres at a height of 10 m from the ground. The running time of the motor to fill the empty water tank is $(g = 10 m s^{- 2})$