Work Energy And Power Question 214

Question: A spring of spring constant $ 5\times 103 N/m $ is stretched initially by 5 cm from the upstretched position. Then the work required to stretch it further by another 5 cm is

Options:

A) 18.75 J

B) 25.00 J

C) 6.25 J

D) 12.50 J

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ {W_1}=\frac{1}{2}\times 5\times 10^{3}{{( 0.05 )}^{2}} $

$ \Rightarrow W_2=\frac{1}{2}\times 5\times 10^{3}{{( 0.10 )}^{2}} $

$ \therefore \Delta W=\frac{1}{2}\times 5\times 10^{3}\times 0.15\times 0.05 =18.75J. $



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