Work Energy And Power Question 208

Question: Calculate the work done on the tool by $ \vec{F}( 11.25\hat{i}+11.25\hat{j} )N $ if the tool is first moved out along the x-axis to the point $ x=3.00m, $

$ y=0 $ and then moved parallel to the y-axis to $ x=3.00m, $

$ y=3.00m $ .

Options:

A) 67.5 J

B) 85 J

C) 102 J

D) 7.5 J

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Net displacement is $ ( 3 \hat{i}+3\hat{j} ) $

so work done $ = \vec{F}.\Delta \vec{s} = 11.25( \hat{i}+\hat{j} ).( 3 \hat{i}+ 3\hat{j} ) $

$ = 33.75 \times 2=67.50 J $



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