Work Energy And Power Question 206

Question: A load hangs from a travelling crane, moving horizontally with velocity v. If the load is not to swing more than 4 m horizontally, when the crane is stopped suddenly, what is the maximum allowable speed of the crane?

Options:

A) 4.05 m/s

B) 4.00 m/s

C) 3.00 m/s

D) 3.50 m/s

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ y=10-\sqrt{10^{2}-4^{2}}=0.84m $

Thus $ \frac{1}{2}mv^{2}=mgy $

Or $ v=\sqrt{2gy}=\sqrt{2\times 9.8\times 0.84} $

$ =4.05m/s. $



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