Work Energy And Power Question 199

Question: A force of 2i^+3j^+4k^ N acts on a body for 4 second, produces a displacement of (3i^+4j^+5k^)m. The power used is [Pb. PET 2001; CBSE PMT 2001]

Options:

A) 9.5 W

B) 7.5 W

C) 6.5 W

D) 4.5 W

Show Answer

Answer:

Correct Answer: A

Solution:

P=F.st=(2i^+3j^+4k^).(3i^+4j^+5k^)4

=384=9.5 W



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