Work Energy And Power Question 170

Question: A neutron having mass of $ 1.67\times {10^{-27}}kg $ and moving at $ 10^{8}m/s $ collides with a deutron at rest and sticks to it. If the mass of the deutron is $ 3.34\times {10^{-27}}kg $ then the speed of the combination is [CBSE PMT 2000]

Options:

A) $ 2.56\times 10^{3}m/s $

B) $ 2.98\times 10^{5}m/s $

C) $ 3.33\times 10^{7}m/s $

D) $ 5.01\times 10^{9}m/s $

Show Answer

Answer:

Correct Answer: C

Solution:

According to law of conservation of momentum.

Momentum of neutron = Momentum of combination therefore $ 1.67\times {10^{-27}}\times 10^{8}=(1.67\times {10^{-27}}+3.34\times {10^{-27}})\ v $ \ $ v=3.33\times 10^{7}m/s $



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