Work Energy And Power Question 164

Question: If a skater of weight 3 kg has initial speed 32 m/s and second one of weight 4 kg has 5 m/s. After collision, they have speed (couple) 5 m/s. Then the loss in K.E. is [CPMT 1996]

Options:

A) 48 J

B) 96 J

C) Zero

D) None of these

Show Answer

Answer:

Correct Answer: D

Solution:

Loss in K.E. = (initial K.E. - Final K.E.) of system $ \frac{1}{2}m_1u_1^{2}+\frac{1}{2}m_2u_2^{2}-\frac{1}{2}(m_1+m_2)V^{2} $

$ =\frac{1}{2}3\times {{(32)}^{2}}+\frac{1}{2}\times 4\times {{(5)}^{2}}-\frac{1}{2}\times (3+4)\times {{(5)}^{2}} $ = 986.5 J



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