SATHEE: Work Energy And Power Question 160

Work Energy And Power Question 160

Question: A 50 g bullet moving with velocity 10 m/s strikes a block of mass 950 g at rest and gets embedded in it. The loss in kinetic energy will be [MP PET 1994]

Options:

A) 100%

B) 95%

C) 5%

D) 50%

Show Answer

Answer:

Correct Answer: B

Solution:

Initial K.E. of system = K.E. of the bullet = $\frac{1}{2} m_{B} v_{B}^{2}$

By the law of conservation of linear momentum $m_{B} v_{B} + 0 = m_{s y s .} \times v_{s y s .}$

therefore $v_{s y s .} = \frac{m_{B} v_{B}}{m_{s y s .}} = \frac{50 \times 10}{50 + 950} = 0.5 m / s$

Fractional loss in K.E. = $\frac{\frac{1}{2} m_{B} v_{B}^{2} - \frac{1}{2} m_{s y s .} v_{s y s .}^{2}}{\frac{1}{2} m_{B} v_{B}^{2}}$

By substituting $m_{B} = 50 \times 10^{- 3} k g, v_{B} = 10 m / s$

$m_{s y s .} = 1 k g, v_{s} = 0.5 m / s$

we get Fractional loss = $\frac{95}{100}$

Percentage loss = 95%

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Work Energy And Power Question 160

Question: A 50 g bullet moving with velocity 10 m/s strikes a block of mass 950 g at rest and gets embedded in it. The loss in kinetic energy will be [MP PET 1994]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu