SATHEE: Work Energy And Power Question 106

Work Energy And Power Question 106

Question: A body of mass 50 kg is projected vertically upwards with velocity of 100 m/sec. 5 seconds after this body breaks into 20 kg and 30 kg. If 20 kg piece travels upwards with 150 m/sec, then the velocity of other block will be [RPMT 1999]

Options:

A) 15 m/sec downwards

B) 15 m/sec upwards

C) 51 m/sec downwards

D) 51 m/sec upwards

Show Answer

Answer:

Correct Answer: A

Solution:

Velocity of 50 kg. mass after 5 sec of projection $v = u - g t$

$= 100 - 9.8 \times 5 = 51 m / s$

At this instant momentum of body is in upward direction $P_{i n i t i a l} = 50 \times 51 = 2550 k g - m / s$

After breaking 20 kg piece travels upwards with 150 m/s let the speed of 30 kg mass is V $P_{f i n a l} = 20 \times 150 + 30 \times V$

By the law of conservation of momentum $P_{initial} = P_{f i n a l}$
therefore $2500 = 20 \times 150 + 30 \times V \Rightarrow V = - 15 m / s$

i.e. it moves in downward direction.

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Work Energy And Power Question 106

Question: A body of mass 50 kg is projected vertically upwards with velocity of 100 m/sec. 5 seconds after this body breaks into 20 kg and 30 kg. If 20 kg piece travels upwards with 150 m/sec, then the velocity of other block will be [RPMT 1999]

Options:

Answer:

Solution:

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