SATHEE: Semiconducting Devices Question 85

Semiconducting Devices Question 85

Question: Sum of the two binary numbers ${(1000010)}_{2}$ and ${(11011)}_{2}$ is

[DCE 2004]

Options:

A) ${(111101)}_{2}$

B) ${(111111)}_{2}$

C) ${(101111)}_{2}$

D) ${(111001)}_{2}$

Show Answer

Answer:

Correct Answer: A

Solution:

${(100010)}_{2} = 2^{5} \times 1 + 2^{4} \times 0 + 2^{3} \times 0 + 2^{2} \times 0 +$

$2^{1} \times 1 + 2^{0} \times 0$

$= 32 + 0 + 0 + 0 + 2 + 0 = {(34)}_{10}$ and

${(11011)}_{2} = 2^{4} \times 1 + 2^{3} \times 1 + 2^{2} \times 0 + 2^{1} \times 1 + 2^{0} \times 1$

$= 16 + 8 + 0 + 2 + 1 = {(27)}_{10}$

Sum

${(100010)}_{2} + {(11011)}_{2}$ =

$34_{10} + 27_{10} = 61_{10}$

Now


2	61	Remainder
2	30	1 LSD
2	15	0
2	7	1
2	3	1
2	1	1
0	1	MSD

Required sum (in binary system)

${(100010)}_{2} + {(11011)}_{2} = {(111101)}_{2}$

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Semiconducting Devices Question 85

Question: Sum of the two binary numbers (1000010)2 and (11011)2 is

Options:

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Question: Sum of the two binary numbers ${(1000010)}_{2}$ and ${(11011)}_{2}$ is