Semiconducting Devices Question 76
Question: A gate has the following truth table [CBSE PMT 2000]
P | 1 1 0 0 |
Q | 1 0 1 0 |
R | 1 0 0 0 |
The gate is
Options:
A) NOR
B) OR
C) NAND
D) AND
Show Answer
Answer:
Correct Answer: D
Solution:
The Boolean expression for AND gate is $ R=P.Q $
Therefore 1.1 = 1, 1.0 = 0, 0.1 = 0, 0.0 = 0