Semiconducting Devices Question 76

Question: A gate has the following truth table [CBSE PMT 2000]
P 1 1 0 0
Q 1 0 1 0
R 1 0 0 0

The gate is

Options:

A) NOR

B) OR

C) NAND

D) AND

Show Answer

Answer:

Correct Answer: D

Solution:

The Boolean expression for AND gate is $ R=P.Q $

Therefore 1.1 = 1, 1.0 = 0, 0.1 = 0, 0.0 = 0



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