Semiconducting Devices Question 59
Question: The relation between Ip and Vp for a triode is $ I _{p}=(0.125V _{p}-7.5)mA $ Keeping the grid potential constant at 1V, the value of rp will be
Options:
A) 8 kW
B) 4 kW
C) 2 kW
D) 8 kW
Show Answer
Answer:
Correct Answer: D
Solution:
$ i _{p}=[0.125V _{p}-7.5]\times {{10}^{-3}}amp $
Differentiating this equation w.r.t.
Vp $ \frac{\Delta i _{p}}{\Delta V _{p}}=0.125\times {{10}^{-3}} $ or $ \frac{1}{r _{p}}=0.125\times {{10}^{-3}} $
Therefore $ r _{p}=8k\Omega $
