Semiconducting Devices Question 54
Question: For the transistor circuit shown below, if b = 100, voltage drop between emitter and base is 0.7 V then value of VCE will be
Options:
A) 10 V
B) 5 V
C) 13 V
D) 0 V
Show Answer
Answer:
Correct Answer: C
Solution:
$ i _{b}=\frac{5-0.7}{8.6}=0.5mA $
Therefore $ I _{c}=\beta I _{b}=100\times 0.5mA $
By using $ V _{CE}=V _{CC}-I _{c}R _{L}=18-50\times {{10}^{-3}}\times 100=13V $
