[CBSE PMT 2001]
A) $ \frac{5}{40}A $
B) $ \frac{5}{50}A $
C) $ \frac{5}{10}A $
D) $ \frac{5}{20}A $
Correct Answer: B
The diode in lower branch is forward biased and diode in upper branch is reverse biased
$ i=\frac{5}{20+30}=\frac{5}{50}A $ .
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