SATHEE: Semiconducting Devices Question 36

Semiconducting Devices Question 36

Question: A P-type semiconductor has acceptor levels 57 meV above the valence band. The maximum wavelength of light required to create a hole is (Planck’s constant h = $6.6 \times 10^{- 34}$ J-s)

[MP PET 1995]

Options:

A) $57 A A$

B) $57 \times 10^{- 3} A A$

C) $217100 A A$

D) $11.61 \times 10^{- 33} A A$

Show Answer

Answer:

Correct Answer: C

Solution:

$E = \frac{h c}{λ}$

Therefore $λ = \frac{h c}{E}$

$= \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{57 \times 10^{- 3} \times 1.6 \times 10^{- 19}}$

$= 217100 A A$ .

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Semiconducting Devices Question 36

Question: A P-type semiconductor has acceptor levels 57 meV above the valence band. The maximum wavelength of light required to create a hole is (Planck’s constant h = 6.6×10−34 J-s)

Options:

Answer:

Solution:

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Question: A P-type semiconductor has acceptor levels 57 meV above the valence band. The maximum wavelength of light required to create a hole is (Planck’s constant h = $6.6 \times 10^{- 34}$ J-s)