Semiconducting Devices Question 32

Question: In PN-junction diode the reverse saturation current is $ {{10}^{-5}} $ amp at $ 27{}^\circ C. $ The forward current for a voltage of $ 0.2volt $ is

[MP PMT 1993]

Options:

A) $ 2037.6\times {{10}^{-3}}amp $

B) $ 203.76\times {{10}^{-3}}amp $

C) $ 20.376\times {{10}^{-3}}amp $

D) $ 2.0376\times 10^{3}amp $

$ [\exp (7.62)=2038.6,K=1.4\times {{10}^{-23}}J/K] $

Show Answer

Answer:

Correct Answer: C

Solution:

The forward current $ i=i _{s}({{e}^{eV/kT}}-1)={{10}^{-5}}[ {{e}^{\frac{1.6\times {{10}^{-19}}\times 0.2}{1.4\times {{10}^{-23}}\times 300}}}-1 ] $

$ ={{10}^{-5}}[2038.6-1]=20.376\times {{10}^{-3}}A $



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