Semiconducting Devices Question 32
Question: In PN-junction diode the reverse saturation current is $ {{10}^{-5}} $ amp at $ 27{}^\circ C. $ The forward current for a voltage of $ 0.2volt $ is
[MP PMT 1993]
Options:
A) $ 2037.6\times {{10}^{-3}}amp $
B) $ 203.76\times {{10}^{-3}}amp $
C) $ 20.376\times {{10}^{-3}}amp $
D) $ 2.0376\times 10^{3}amp $
$ [\exp (7.62)=2038.6,K=1.4\times {{10}^{-23}}J/K] $
Show Answer
Answer:
Correct Answer: C
Solution:
The forward current $ i=i _{s}({{e}^{eV/kT}}-1)={{10}^{-5}}[ {{e}^{\frac{1.6\times {{10}^{-19}}\times 0.2}{1.4\times {{10}^{-23}}\times 300}}}-1 ] $
$ ={{10}^{-5}}[2038.6-1]=20.376\times {{10}^{-3}}A $
